{
"cells": [
{
"cell_type": "markdown",
"id": "b4886f2a",
"metadata": {
"origin_pos": 0
},
"source": [
"# AdaGrad算法\n",
":label:`sec_adagrad`\n",
"\n",
"我们从有关特征学习中并不常见的问题入手。\n",
"\n",
"## 稀疏特征和学习率\n",
"\n",
"假设我们正在训练一个语言模型。\n",
"为了获得良好的准确性,我们大多希望在训练的过程中降低学习率,速度通常为$\\mathcal{O}(t^{-\\frac{1}{2}})$或更低。\n",
"现在讨论关于稀疏特征(即只在偶尔出现的特征)的模型训练,这对自然语言来说很常见。\n",
"例如,我们看到“预先条件”这个词比“学习”这个词的可能性要小得多。\n",
"但是,它在计算广告学和个性化协同过滤等其他领域也很常见。\n",
"\n",
"只有在这些不常见的特征出现时,与其相关的参数才会得到有意义的更新。\n",
"鉴于学习率下降,我们可能最终会面临这样的情况:常见特征的参数相当迅速地收敛到最佳值,而对于不常见的特征,我们仍缺乏足够的观测以确定其最佳值。\n",
"换句话说,学习率要么对于常见特征而言降低太慢,要么对于不常见特征而言降低太快。\n",
"\n",
"解决此问题的一个方法是记录我们看到特定特征的次数,然后将其用作调整学习率。\n",
"即我们可以使用大小为$\\eta_i = \\frac{\\eta_0}{\\sqrt{s(i, t) + c}}$的学习率,而不是$\\eta = \\frac{\\eta_0}{\\sqrt{t + c}}$。\n",
"在这里$s(i, t)$计下了我们截至$t$时观察到功能$i$的次数。\n",
"这其实很容易实施且不产生额外损耗。\n",
"\n",
"AdaGrad算法 :cite:`Duchi.Hazan.Singer.2011`通过将粗略的计数器$s(i, t)$替换为先前观察所得梯度的平方之和来解决这个问题。\n",
"它使用$s(i, t+1) = s(i, t) + \\left(\\partial_i f(\\mathbf{x})\\right)^2$来调整学习率。\n",
"这有两个好处:首先,我们不再需要决定梯度何时算足够大。\n",
"其次,它会随梯度的大小自动变化。通常对应于较大梯度的坐标会显著缩小,而其他梯度较小的坐标则会得到更平滑的处理。\n",
"在实际应用中,它促成了计算广告学及其相关问题中非常有效的优化程序。\n",
"但是,它遮盖了AdaGrad固有的一些额外优势,这些优势在预处理环境中很容易被理解。\n",
"\n",
"## 预处理\n",
"\n",
"凸优化问题有助于分析算法的特点。\n",
"毕竟对大多数非凸问题来说,获得有意义的理论保证很难,但是直觉和洞察往往会延续。\n",
"让我们来看看最小化$f(\\mathbf{x}) = \\frac{1}{2} \\mathbf{x}^\\top \\mathbf{Q} \\mathbf{x} + \\mathbf{c}^\\top \\mathbf{x} + b$这一问题。\n",
"\n",
"正如在 :numref:`sec_momentum`中那样,我们可以根据其特征分解$\\mathbf{Q} = \\mathbf{U}^\\top \\boldsymbol{\\Lambda} \\mathbf{U}$重写这个问题,来得到一个简化得多的问题,使每个坐标都可以单独解出:\n",
"\n",
"$$f(\\mathbf{x}) = \\bar{f}(\\bar{\\mathbf{x}}) = \\frac{1}{2} \\bar{\\mathbf{x}}^\\top \\boldsymbol{\\Lambda} \\bar{\\mathbf{x}} + \\bar{\\mathbf{c}}^\\top \\bar{\\mathbf{x}} + b.$$\n",
"\n",
"在这里我们使用了$\\mathbf{x} = \\mathbf{U} \\mathbf{x}$,且因此$\\mathbf{c} = \\mathbf{U} \\mathbf{c}$。\n",
"修改后优化器为$\\bar{\\mathbf{x}} = -\\boldsymbol{\\Lambda}^{-1} \\bar{\\mathbf{c}}$且最小值为$-\\frac{1}{2} \\bar{\\mathbf{c}}^\\top \\boldsymbol{\\Lambda}^{-1} \\bar{\\mathbf{c}} + b$。\n",
"这样更容易计算,因为$\\boldsymbol{\\Lambda}$是一个包含$\\mathbf{Q}$特征值的对角矩阵。\n",
"\n",
"如果稍微扰动$\\mathbf{c}$,我们会期望在$f$的最小化器中只产生微小的变化。\n",
"遗憾的是,情况并非如此。\n",
"虽然$\\mathbf{c}$的微小变化导致了$\\bar{\\mathbf{c}}$同样的微小变化,但$f$的(以及$\\bar{f}$的)最小化器并非如此。\n",
"每当特征值$\\boldsymbol{\\Lambda}_i$很大时,我们只会看到$\\bar{x}_i$和$\\bar{f}$的最小值发声微小变化。\n",
"相反,对小的$\\boldsymbol{\\Lambda}_i$来说,$\\bar{x}_i$的变化可能是剧烈的。\n",
"最大和最小的特征值之比称为优化问题的*条件数*(condition number)。\n",
"\n",
"$$\\kappa = \\frac{\\boldsymbol{\\Lambda}_1}{\\boldsymbol{\\Lambda}_d}.$$\n",
"\n",
"如果条件编号$\\kappa$很大,准确解决优化问题就会很难。\n",
"我们需要确保在获取大量动态的特征值范围时足够谨慎:难道我们不能简单地通过扭曲空间来“修复”这个问题,从而使所有特征值都是$1$?\n",
"理论上这很容易:我们只需要$\\mathbf{Q}$的特征值和特征向量即可将问题从$\\mathbf{x}$整理到$\\mathbf{z} := \\boldsymbol{\\Lambda}^{\\frac{1}{2}} \\mathbf{U} \\mathbf{x}$中的一个。\n",
"在新的坐标系中,$\\mathbf{x}^\\top \\mathbf{Q} \\mathbf{x}$可以被简化为$\\|\\mathbf{z}\\|^2$。\n",
"可惜,这是一个相当不切实际的想法。\n",
"一般而言,计算特征值和特征向量要比解决实际问题“贵”得多。\n",
"\n",
"虽然准确计算特征值可能会很昂贵,但即便只是大致猜测并计算它们,也可能已经比不做任何事情好得多。\n",
"特别是,我们可以使用$\\mathbf{Q}$的对角线条目并相应地重新缩放它。\n",
"这比计算特征值开销小的多。\n",
"\n",
"$$\\tilde{\\mathbf{Q}} = \\mathrm{diag}^{-\\frac{1}{2}}(\\mathbf{Q}) \\mathbf{Q} \\mathrm{diag}^{-\\frac{1}{2}}(\\mathbf{Q}).$$\n",
"\n",
"在这种情况下,我们得到了$\\tilde{\\mathbf{Q}}_{ij} = \\mathbf{Q}_{ij} / \\sqrt{\\mathbf{Q}_{ii} \\mathbf{Q}_{jj}}$,特别注意对于所有$i$,$\\tilde{\\mathbf{Q}}_{ii} = 1$。\n",
"在大多数情况下,这大大简化了条件数。\n",
"例如我们之前讨论的案例,它将完全消除眼下的问题,因为问题是轴对齐的。\n",
"\n",
"遗憾的是,我们还面临另一个问题:在深度学习中,我们通常情况甚至无法计算目标函数的二阶导数:对于$\\mathbf{x} \\in \\mathbb{R}^d$,即使只在小批量上,二阶导数可能也需要$\\mathcal{O}(d^2)$空间来计算,导致几乎不可行。\n",
"AdaGrad算法巧妙的思路是,使用一个代理来表示黑塞矩阵(Hessian)的对角线,既相对易于计算又高效。\n",
"\n",
"为了了解它是如何生效的,让我们来看看$\\bar{f}(\\bar{\\mathbf{x}})$。\n",
"我们有\n",
"\n",
"$$\\partial_{\\bar{\\mathbf{x}}} \\bar{f}(\\bar{\\mathbf{x}}) = \\boldsymbol{\\Lambda} \\bar{\\mathbf{x}} + \\bar{\\mathbf{c}} = \\boldsymbol{\\Lambda} \\left(\\bar{\\mathbf{x}} - \\bar{\\mathbf{x}}_0\\right),$$\n",
"\n",
"其中$\\bar{\\mathbf{x}}_0$是$\\bar{f}$的优化器。\n",
"因此,梯度的大小取决于$\\boldsymbol{\\Lambda}$和与最佳值的差值。\n",
"如果$\\bar{\\mathbf{x}} - \\bar{\\mathbf{x}}_0$没有改变,那这就是我们所求的。\n",
"毕竟在这种情况下,梯度$\\partial_{\\bar{\\mathbf{x}}} \\bar{f}(\\bar{\\mathbf{x}})$的大小就足够了。\n",
"由于AdaGrad算法是一种随机梯度下降算法,所以即使是在最佳值中,我们也会看到具有非零方差的梯度。\n",
"因此,我们可以放心地使用梯度的方差作为黑塞矩阵比例的廉价替代。\n",
"详尽的分析(要花几页解释)超出了本节的范围,请读者参考 :cite:`Duchi.Hazan.Singer.2011`。\n",
"\n",
"## 算法\n",
"\n",
"让我们接着上面正式开始讨论。\n",
"我们使用变量$\\mathbf{s}_t$来累加过去的梯度方差,如下所示:\n",
"\n",
"$$\\begin{aligned}\n",
" \\mathbf{g}_t & = \\partial_{\\mathbf{w}} l(y_t, f(\\mathbf{x}_t, \\mathbf{w})), \\\\\n",
" \\mathbf{s}_t & = \\mathbf{s}_{t-1} + \\mathbf{g}_t^2, \\\\\n",
" \\mathbf{w}_t & = \\mathbf{w}_{t-1} - \\frac{\\eta}{\\sqrt{\\mathbf{s}_t + \\epsilon}} \\cdot \\mathbf{g}_t.\n",
"\\end{aligned}$$\n",
"\n",
"在这里,操作是按照坐标顺序应用。\n",
"也就是说,$\\mathbf{v}^2$有条目$v_i^2$。\n",
"同样,$\\frac{1}{\\sqrt{v}}$有条目$\\frac{1}{\\sqrt{v_i}}$,\n",
"并且$\\mathbf{u} \\cdot \\mathbf{v}$有条目$u_i v_i$。\n",
"与之前一样,$\\eta$是学习率,$\\epsilon$是一个为维持数值稳定性而添加的常数,用来确保我们不会除以$0$。\n",
"最后,我们初始化$\\mathbf{s}_0 = \\mathbf{0}$。\n",
"\n",
"就像在动量法中我们需要跟踪一个辅助变量一样,在AdaGrad算法中,我们允许每个坐标有单独的学习率。\n",
"与SGD算法相比,这并没有明显增加AdaGrad的计算代价,因为主要计算用在$l(y_t, f(\\mathbf{x}_t, \\mathbf{w}))$及其导数。\n",
"\n",
"请注意,在$\\mathbf{s}_t$中累加平方梯度意味着$\\mathbf{s}_t$基本上以线性速率增长(由于梯度从最初开始衰减,实际上比线性慢一些)。\n",
"这产生了一个学习率$\\mathcal{O}(t^{-\\frac{1}{2}})$,但是在单个坐标的层面上进行了调整。\n",
"对于凸问题,这完全足够了。\n",
"然而,在深度学习中,我们可能希望更慢地降低学习率。\n",
"这引出了许多AdaGrad算法的变体,我们将在后续章节中讨论它们。\n",
"眼下让我们先看看它在二次凸问题中的表现如何。\n",
"我们仍然以同一函数为例:\n",
"\n",
"$$f(\\mathbf{x}) = 0.1 x_1^2 + 2 x_2^2.$$\n",
"\n",
"我们将使用与之前相同的学习率来实现AdaGrad算法,即$\\eta = 0.4$。\n",
"可以看到,自变量的迭代轨迹较平滑。\n",
"但由于$\\boldsymbol{s}_t$的累加效果使学习率不断衰减,自变量在迭代后期的移动幅度较小。\n"
]
},
{
"cell_type": "code",
"execution_count": 1,
"id": "f2d18ce2",
"metadata": {
"execution": {
"iopub.execute_input": "2023-08-18T07:07:35.660003Z",
"iopub.status.busy": "2023-08-18T07:07:35.659452Z",
"iopub.status.idle": "2023-08-18T07:07:37.668048Z",
"shell.execute_reply": "2023-08-18T07:07:37.667136Z"
},
"origin_pos": 2,
"tab": [
"pytorch"
]
},
"outputs": [],
"source": [
"%matplotlib inline\n",
"import math\n",
"import torch\n",
"from d2l import torch as d2l"
]
},
{
"cell_type": "code",
"execution_count": 2,
"id": "db64eb41",
"metadata": {
"execution": {
"iopub.execute_input": "2023-08-18T07:07:37.671920Z",
"iopub.status.busy": "2023-08-18T07:07:37.671523Z",
"iopub.status.idle": "2023-08-18T07:07:37.815807Z",
"shell.execute_reply": "2023-08-18T07:07:37.814923Z"
},
"origin_pos": 5,
"tab": [
"pytorch"
]
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"epoch 20, x1: -2.382563, x2: -0.158591\n"
]
},
{
"data": {
"image/svg+xml": [
"\n",
"\n",
"\n"
],
"text/plain": [
""
]
},
"metadata": {
"needs_background": "light"
},
"output_type": "display_data"
}
],
"source": [
"def adagrad_2d(x1, x2, s1, s2):\n",
" eps = 1e-6\n",
" g1, g2 = 0.2 * x1, 4 * x2\n",
" s1 += g1 ** 2\n",
" s2 += g2 ** 2\n",
" x1 -= eta / math.sqrt(s1 + eps) * g1\n",
" x2 -= eta / math.sqrt(s2 + eps) * g2\n",
" return x1, x2, s1, s2\n",
"\n",
"def f_2d(x1, x2):\n",
" return 0.1 * x1 ** 2 + 2 * x2 ** 2\n",
"\n",
"eta = 0.4\n",
"d2l.show_trace_2d(f_2d, d2l.train_2d(adagrad_2d))"
]
},
{
"cell_type": "markdown",
"id": "a777f665",
"metadata": {
"origin_pos": 6
},
"source": [
"我们将学习率提高到$2$,可以看到更好的表现。\n",
"这已经表明,即使在无噪声的情况下,学习率的降低可能相当剧烈,我们需要确保参数能够适当地收敛。\n"
]
},
{
"cell_type": "code",
"execution_count": 3,
"id": "7f344858",
"metadata": {
"execution": {
"iopub.execute_input": "2023-08-18T07:07:37.819405Z",
"iopub.status.busy": "2023-08-18T07:07:37.819092Z",
"iopub.status.idle": "2023-08-18T07:07:37.956764Z",
"shell.execute_reply": "2023-08-18T07:07:37.955622Z"
},
"origin_pos": 7,
"tab": [
"pytorch"
]
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"epoch 20, x1: -0.002295, x2: -0.000000\n"
]
},
{
"data": {
"image/svg+xml": [
"\n",
"\n",
"\n"
],
"text/plain": [
""
]
},
"metadata": {
"needs_background": "light"
},
"output_type": "display_data"
}
],
"source": [
"eta = 2\n",
"d2l.show_trace_2d(f_2d, d2l.train_2d(adagrad_2d))"
]
},
{
"cell_type": "markdown",
"id": "0fb2a2e5",
"metadata": {
"origin_pos": 8
},
"source": [
"## 从零开始实现\n",
"\n",
"同动量法一样,AdaGrad算法需要对每个自变量维护同它一样形状的状态变量。\n"
]
},
{
"cell_type": "code",
"execution_count": 4,
"id": "e69612f9",
"metadata": {
"execution": {
"iopub.execute_input": "2023-08-18T07:07:37.961770Z",
"iopub.status.busy": "2023-08-18T07:07:37.961458Z",
"iopub.status.idle": "2023-08-18T07:07:37.967644Z",
"shell.execute_reply": "2023-08-18T07:07:37.966629Z"
},
"origin_pos": 10,
"tab": [
"pytorch"
]
},
"outputs": [],
"source": [
"def init_adagrad_states(feature_dim):\n",
" s_w = torch.zeros((feature_dim, 1))\n",
" s_b = torch.zeros(1)\n",
" return (s_w, s_b)\n",
"\n",
"def adagrad(params, states, hyperparams):\n",
" eps = 1e-6\n",
" for p, s in zip(params, states):\n",
" with torch.no_grad():\n",
" s[:] += torch.square(p.grad)\n",
" p[:] -= hyperparams['lr'] * p.grad / torch.sqrt(s + eps)\n",
" p.grad.data.zero_()"
]
},
{
"cell_type": "markdown",
"id": "3abf8b9a",
"metadata": {
"origin_pos": 13
},
"source": [
"与 :numref:`sec_minibatch_sgd`一节中的实验相比,这里使用更大的学习率来训练模型。\n"
]
},
{
"cell_type": "code",
"execution_count": 5,
"id": "82c63a0b",
"metadata": {
"execution": {
"iopub.execute_input": "2023-08-18T07:07:37.971150Z",
"iopub.status.busy": "2023-08-18T07:07:37.970847Z",
"iopub.status.idle": "2023-08-18T07:07:40.594904Z",
"shell.execute_reply": "2023-08-18T07:07:40.593847Z"
},
"origin_pos": 14,
"tab": [
"pytorch"
]
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"loss: 0.242, 0.012 sec/epoch\n"
]
},
{
"data": {
"image/svg+xml": [
"\n",
"\n",
"\n"
],
"text/plain": [
""
]
},
"metadata": {
"needs_background": "light"
},
"output_type": "display_data"
}
],
"source": [
"data_iter, feature_dim = d2l.get_data_ch11(batch_size=10)\n",
"d2l.train_ch11(adagrad, init_adagrad_states(feature_dim),\n",
" {'lr': 0.1}, data_iter, feature_dim);"
]
},
{
"cell_type": "markdown",
"id": "1903affc",
"metadata": {
"origin_pos": 15
},
"source": [
"## 简洁实现\n",
"\n",
"我们可直接使用深度学习框架中提供的AdaGrad算法来训练模型。\n"
]
},
{
"cell_type": "code",
"execution_count": 6,
"id": "c7c10ee3",
"metadata": {
"execution": {
"iopub.execute_input": "2023-08-18T07:07:40.599038Z",
"iopub.status.busy": "2023-08-18T07:07:40.598462Z",
"iopub.status.idle": "2023-08-18T07:07:45.691770Z",
"shell.execute_reply": "2023-08-18T07:07:45.690969Z"
},
"origin_pos": 17,
"tab": [
"pytorch"
]
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"loss: 0.242, 0.013 sec/epoch\n"
]
},
{
"data": {
"image/svg+xml": [
"\n",
"\n",
"\n"
],
"text/plain": [
""
]
},
"metadata": {
"needs_background": "light"
},
"output_type": "display_data"
}
],
"source": [
"trainer = torch.optim.Adagrad\n",
"d2l.train_concise_ch11(trainer, {'lr': 0.1}, data_iter)"
]
},
{
"cell_type": "markdown",
"id": "7c70fc97",
"metadata": {
"origin_pos": 20
},
"source": [
"## 小结\n",
"\n",
"* AdaGrad算法会在单个坐标层面动态降低学习率。\n",
"* AdaGrad算法利用梯度的大小作为调整进度速率的手段:用较小的学习率来补偿带有较大梯度的坐标。\n",
"* 在深度学习问题中,由于内存和计算限制,计算准确的二阶导数通常是不可行的。梯度可以作为一个有效的代理。\n",
"* 如果优化问题的结构相当不均匀,AdaGrad算法可以帮助缓解扭曲。\n",
"* AdaGrad算法对于稀疏特征特别有效,在此情况下由于不常出现的问题,学习率需要更慢地降低。\n",
"* 在深度学习问题上,AdaGrad算法有时在降低学习率方面可能过于剧烈。我们将在 :numref:`sec_adam`一节讨论缓解这种情况的策略。\n",
"\n",
"## 练习\n",
"\n",
"1. 证明对于正交矩阵$\\mathbf{U}$和向量$\\mathbf{c}$,以下等式成立:$\\|\\mathbf{c} - \\mathbf{\\delta}\\|_2 = \\|\\mathbf{U} \\mathbf{c} - \\mathbf{U} \\mathbf{\\delta}\\|_2$。为什么这意味着在变量的正交变化之后,扰动的程度不会改变?\n",
"1. 尝试对函数$f(\\mathbf{x}) = 0.1 x_1^2 + 2 x_2^2$、以及它旋转45度后的函数即$f(\\mathbf{x}) = 0.1 (x_1 + x_2)^2 + 2 (x_1 - x_2)^2$使用AdaGrad算法。它的表现会不同吗?\n",
"1. 证明[格什戈林圆盘定理](https://en.wikipedia.org/wiki/Gershgorin_circle_theorem),其中提到,矩阵$\\mathbf{M}$的特征值$\\lambda_i$在至少一个$j$的选项中满足$|\\lambda_i - \\mathbf{M}_{jj}| \\leq \\sum_{k \\neq j} |\\mathbf{M}_{jk}|$的要求。\n",
"1. 关于对角线预处理矩阵$\\mathrm{diag}^{-\\frac{1}{2}}(\\mathbf{M}) \\mathbf{M} \\mathrm{diag}^{-\\frac{1}{2}}(\\mathbf{M})$的特征值,格什戈林的定理告诉了我们什么?\n",
"1. 尝试对适当的深度网络使用AdaGrad算法,例如,:numref:`sec_lenet`中应用于Fashion-MNIST的深度网络。\n",
"1. 要如何修改AdaGrad算法,才能使其在学习率方面的衰减不那么激进?\n"
]
},
{
"cell_type": "markdown",
"id": "6fb87f9b",
"metadata": {
"origin_pos": 22,
"tab": [
"pytorch"
]
},
"source": [
"[Discussions](https://discuss.d2l.ai/t/4319)\n"
]
}
],
"metadata": {
"language_info": {
"name": "python"
},
"required_libs": []
},
"nbformat": 4,
"nbformat_minor": 5
}